程序员如何实现财富自由系列之：利用程序员技能成为游戏开发者

       if k > 0:

       for c in range(len(colors)):
           dp[i+1][c] = max(dp[i+1][c], dp[i][0]*p_color[c]) # 在第一个房间中选 c 件衣服
           dp[i+1][c] = max(dp[i+1][c], dp[i][1]*p_color[(c + 1) % len(colors)]) # 在第二个房间中选 c 件衣服
    
       else:
       for c in range(len(colors)):
           dp[i+1][c] = dp[i][0]*p_color[c] # 空集情况
    
       dp[i+1][(c+1)%len(colors)] += p_same[c] * (n-(i+1))
    
         
         
         
         
         
         
         
         
         
    代码解读

    def placeQueens(board):
    # 检查是否可以放置皇后
    def isValid(row, col):
        for r in range(row):
            if board[r] == col or abs(col - board[r]) == row - r:
                return False
        return True
    
    n = len(board)
    col = 0
    
    while col < n:
        row = len(list(filter(lambda x : x!= None, board)))
    
        if not isValid(row, col):
            break
    
        board[row] = col
        placeQueens(board)
        del board[-1]
    
    print(board)
    
    if __name__ == '__main__':
    board = [None] 
    placeQueens(board)
    
      
      
      
      
      
      
      
      
      
      
      
      
      
      
      
      
      
      
      
      
      
      
      
      
      
    
    代码解读

    Input array: {5, 2, 7, 3}
    Output sorted array: {2, 3, 5, 7}
    
    Step 1: Insertion sort on the second element of the input array
    {2, **5**, 7, 3}
    {2, **2**, 7, 3} // This step is skipped because the previous element is smaller than the current one
    {**2**, 5, 7, 3}
    {2, **3**, 7, 5}
    
    Step 2: Insertion sort on the third element of the input array
    {2, 3, **7**, 5}
    {2, 3, **5**, 7} // This step swaps with the first element to maintain ascending order
    {2, 3, **5**, 7} 
    
    Sorted array after completing both steps: {2, 3, 5, 7}
    
      
      
      
      
      
      
      
      
      
      
      
      
      
      
    
    代码解读

    Input array: {5, 2, 7, 3}
    Output sorted array: {2, 3, 5, 7}
    
    First pass: Find the smallest value and swap it with the leftmost value, leaving {2, 5, 7, 3}. 
    Second pass: Find the smallest value that's greater than 2 and swap it with 5, resulting in {2, 3, 7, 5}.
    Third pass: The remaining values are already sorted, so we stop here. We end up with the final sorted array: {2, 3, 5, 7}.
    
      
      
      
      
      
    
    代码解读

    Input array: {5, 2, 7, 3}
    Output sorted array: {2, 3, 5, 7}
    
    Pass 1: {5, 2, 7, 3} // Compare 5 and 2, swap them since 5 > 2
    {2, 5, 7, 3}
    
    Pass 2: {2, 5, 7, 3} // Compare 5 and 7, no swap needed
    {2, 5, 7, 3}
    
    Pass 3: {2, 5, 3, 7} // Compare 5 and 3, swap them since 5 < 3
    {2, 3, 5, 7}
    
    Pass 4: {2, 3, 5, 7} // The list is now fully sorted
    {2, 3, 5, 7}
    
      
      
      
      
      
      
      
      
      
      
      
      
      
    
    代码解读

    Input array: {5, 2, 7, 3}
    Output sorted array: {2, 3, 5, 7}
    
    Choose pivot as 3
    {2, 5, 7}, 3, {3} 
    
    Recursively apply quicksort algorithm to the two sublists {2, 5, 7} and {} until they become single elements. 
    
    Sublist {2, 5, 7}: Choose pivot as 5 
    {}, 5, {2, 7} 
    
    Recursive call to {2, 7}: base case reached. Swap 5 and 7 to get {}, 7, {2}. Sublist becomes {2}.
    
    Sublist {}: Base case reached. Swap 2 and {} to get {2}, 7, {}. Sorted sublist remains empty. 
    
    The final sorted array is {2, 3, 5, 7}.
    
      
      
      
      
      
      
      
      
      
      
      
      
      
      
      
    
    代码解读

    Input array: {5, 2, 7, 3}
    Output sorted array: {2, 3, 5, 7}
    
    Build heap from array {5, 2, 7, 3}: {5}, {2, 7}, {2, 3, 7}
    
    Heapify the root node of each heap, resulting in {5, 7}, {3, 7, 2}
    
    Swap the last two elements of each heap, resulting in {5, 7}, {2, 3, 7}
    
    Add the largest element back into its original position, resulting in {5, 2, 7, 3}
    
    Finally, the result array is {2, 3, 5, 7}.
    
      
      
      
      
      
      
      
      
      
      
      
    
    代码解读

    Input array: {5, 2, 7, 3, 5, 2, 7}
    Output sorted array: {2, 2, 3, 5, 5, 7, 7}
    
    Count occurrences of each number in the input array:
    {5, 2, 7, 3} => {0, 1, 2, 1}
    
    Create an output array by using this count information: {2, 1, 3, 0, 0, 2, 1}
    
    Apply decreasing order counting method to get the final result: {2, 2, 3, 5, 5, 7, 7}
    
      
      
      
      
      
      
      
      
    
    代码解读

    Input array: {5, 2, 7, 3, 5, 2, 7}
    Output sorted array: {2, 2, 3, 5, 5, 7, 7}
    
    Set numBuckets equal to sqrt(|inputArray|)
    {5, 2, 7, 3, 5, 2, 7} -> {5, 2, 7, 3, }, {, }
    
    Sort elements within each bucket using any comparison-based sorting algorithm such as insertion sort
      {5}, {2, 7}, {3} 
    
    Merge all buckets together to produce the final output: {2, 2, 3, 5, 5, 7, 7}
    
      
      
      
      
      
      
      
      
      
    
    代码解读