上海市计算机学会月赛2020年3月丙组
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打渔还是晒网
    #include <bits/stdc++.h>
    using namespace std;
    
    int main() {
    	int n;
    	cin >> n;
    	
    	if (n % 5 == 0 || n % 5 == 4) {	//后两天晒网 
    		cout << "Lying" << endl;
    	}
    	else {
    		cout << "Fishing" << endl;	//前三天打渔 
    	}
    	
    	return 0;
    }
        数字加密
    #include <bits/stdc++.h>
    using namespace std;
    
    int main() {
    	char c[4];
    	cin >> c;
    	
    	for (int i = 3; i >= 0; i --) {		//倒过来枚举 
    		//'9' - c[i]得到对调后的数字 
    		//'9' - c[i]得到对调后的数字的ASCII码 
    		cout << char('9' - c[i] + '0');
    	}
    	
    	return 0;
    }
        双质数
    #include <bits/stdc++.h>
    using namespace std;
    
    bool isPrime(int x) {
    	if (x < 2) return false;		//特判 
    	
    	for (int i = 2; i <= x / i; i ++) {
    		if (x % i == 0) {
    			return false;
    		}
    	}
    	return true;
    }
    
    int main() {
    	int a, b;
    	cin >> a >> b;
    	
    	bool flag = false;	
    	for (int i = a; i <= b; i++) {
    		if (isPrime(i) && isPrime(i / 10)) {
    			cout << i << endl;
    			flag = true;
    		}
    	}
    	
    	if (!flag) {		//说明没有找到双质数 
    		cout << "None" << endl;
    	}
    	
    	return 0;
    }
        连乘问题
    #include <bits/stdc++.h>
    using namespace std;
    
    const int N = 1e5 + 9, MOD = 1e4;
    int n, a[N], b[N], c[N];
    
    int main() {
    	scanf("%d", &n);	
    	for (int i = 1; i <= n; i ++) {
    		scanf("%d", &a[i]);
    	}
    	
    	b[0] = 1;
    	for (int i = 1; i <= n; i ++) {			//前缀积 
    		b[i] = b[i - 1] * a[i] % MOD;
    	}
    	
    	c[n + 1] = 1;
    	for (int i = n; i >= 1; i --) { 		//后缀积 
    		c[i] = c[i + 1] * a[i] % MOD;
    	}	
    	
    	for (int i = 1; i <= n; i ++) {
    		printf("%d\n", b[i - 1] * c[i + 1] % MOD);
    	}
    	
    	return 0;
    }
        救援争先
    #include <bits/stdc++.h>
    using namespace std;
    
    int n;
    struct team{
    	int depart, arrive, id;
    }t[1005];
    
    bool cmp(team a, team b) {
    	if (a.arrive < b.arrive) return true;
    	if (a.arrive == b.arrive) {
    		if (a.depart < b.depart) return true;
    		if (a.depart == b.depart) {
    			if (a.id < b.id) return true;			
    		}
    	}
    	return false;
    }
    
    int main() {
    	cin >> n;	
    	for (int i = 1; i <= n; i ++) {
    		int x, y;
    		char ch;
    		
    		cin >> x >> ch >> y;
    		t[i].depart = x * 60 + y;				//第i只队伍的出发时间 
    		
    		cin >> x >> ch >> y;
    		t[i].arrive = t[i].depart + x * 60 + y;	//第i只队伍的到达时间
    		
    		t[i].id = i;							//第i只队伍的编号 
    	}
    
    	sort(t + 1, t + 1 + n, cmp);				//根据题目中的规则进行排序 
    
    	for (int i = 1; i <= n; i ++) cout << t[i].id << endl;
    
    	return 0;
    }
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